\(\int \frac {(a+b \log (c x^n))^2}{x^2 (d+e x)^3} \, dx\) [112]

   Optimal result
   Rubi [A] (verified)
   Mathematica [A] (verified)
   Maple [C] (warning: unable to verify)
   Fricas [F]
   Sympy [F]
   Maxima [F]
   Giac [F]
   Mupad [F(-1)]

Optimal result

Integrand size = 23, antiderivative size = 322 \[ \int \frac {\left (a+b \log \left (c x^n\right )\right )^2}{x^2 (d+e x)^3} \, dx=-\frac {2 b^2 n^2}{d^3 x}-\frac {2 b n \left (a+b \log \left (c x^n\right )\right )}{d^3 x}-\frac {b e^2 n x \left (a+b \log \left (c x^n\right )\right )}{d^4 (d+e x)}+\frac {e \left (a+b \log \left (c x^n\right )\right )^2}{2 d^4}-\frac {\left (a+b \log \left (c x^n\right )\right )^2}{d^3 x}-\frac {e \left (a+b \log \left (c x^n\right )\right )^2}{2 d^2 (d+e x)^2}+\frac {2 e^2 x \left (a+b \log \left (c x^n\right )\right )^2}{d^4 (d+e x)}-\frac {e \left (a+b \log \left (c x^n\right )\right )^3}{b d^4 n}+\frac {b^2 e n^2 \log (d+e x)}{d^4}-\frac {5 b e n \left (a+b \log \left (c x^n\right )\right ) \log \left (1+\frac {e x}{d}\right )}{d^4}+\frac {3 e \left (a+b \log \left (c x^n\right )\right )^2 \log \left (1+\frac {e x}{d}\right )}{d^4}-\frac {5 b^2 e n^2 \operatorname {PolyLog}\left (2,-\frac {e x}{d}\right )}{d^4}+\frac {6 b e n \left (a+b \log \left (c x^n\right )\right ) \operatorname {PolyLog}\left (2,-\frac {e x}{d}\right )}{d^4}-\frac {6 b^2 e n^2 \operatorname {PolyLog}\left (3,-\frac {e x}{d}\right )}{d^4} \]

[Out]

-2*b^2*n^2/d^3/x-2*b*n*(a+b*ln(c*x^n))/d^3/x-b*e^2*n*x*(a+b*ln(c*x^n))/d^4/(e*x+d)+1/2*e*(a+b*ln(c*x^n))^2/d^4
-(a+b*ln(c*x^n))^2/d^3/x-1/2*e*(a+b*ln(c*x^n))^2/d^2/(e*x+d)^2+2*e^2*x*(a+b*ln(c*x^n))^2/d^4/(e*x+d)-e*(a+b*ln
(c*x^n))^3/b/d^4/n+b^2*e*n^2*ln(e*x+d)/d^4-5*b*e*n*(a+b*ln(c*x^n))*ln(1+e*x/d)/d^4+3*e*(a+b*ln(c*x^n))^2*ln(1+
e*x/d)/d^4-5*b^2*e*n^2*polylog(2,-e*x/d)/d^4+6*b*e*n*(a+b*ln(c*x^n))*polylog(2,-e*x/d)/d^4-6*b^2*e*n^2*polylog
(3,-e*x/d)/d^4

Rubi [A] (verified)

Time = 0.34 (sec) , antiderivative size = 335, normalized size of antiderivative = 1.04, number of steps used = 16, number of rules used = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.565, Rules used = {2395, 2342, 2341, 2356, 2389, 2379, 2438, 2351, 31, 2355, 2354, 2421, 6724} \[ \int \frac {\left (a+b \log \left (c x^n\right )\right )^2}{x^2 (d+e x)^3} \, dx=\frac {2 e^2 x \left (a+b \log \left (c x^n\right )\right )^2}{d^4 (d+e x)}-\frac {b e^2 n x \left (a+b \log \left (c x^n\right )\right )}{d^4 (d+e x)}-\frac {6 b e n \operatorname {PolyLog}\left (2,-\frac {d}{e x}\right ) \left (a+b \log \left (c x^n\right )\right )}{d^4}+\frac {3 e \log \left (\frac {d}{e x}+1\right ) \left (a+b \log \left (c x^n\right )\right )^2}{d^4}-\frac {b e n \log \left (\frac {d}{e x}+1\right ) \left (a+b \log \left (c x^n\right )\right )}{d^4}-\frac {4 b e n \log \left (\frac {e x}{d}+1\right ) \left (a+b \log \left (c x^n\right )\right )}{d^4}-\frac {\left (a+b \log \left (c x^n\right )\right )^2}{d^3 x}-\frac {2 b n \left (a+b \log \left (c x^n\right )\right )}{d^3 x}-\frac {e \left (a+b \log \left (c x^n\right )\right )^2}{2 d^2 (d+e x)^2}+\frac {b^2 e n^2 \operatorname {PolyLog}\left (2,-\frac {d}{e x}\right )}{d^4}-\frac {4 b^2 e n^2 \operatorname {PolyLog}\left (2,-\frac {e x}{d}\right )}{d^4}-\frac {6 b^2 e n^2 \operatorname {PolyLog}\left (3,-\frac {d}{e x}\right )}{d^4}+\frac {b^2 e n^2 \log (d+e x)}{d^4}-\frac {2 b^2 n^2}{d^3 x} \]

[In]

Int[(a + b*Log[c*x^n])^2/(x^2*(d + e*x)^3),x]

[Out]

(-2*b^2*n^2)/(d^3*x) - (2*b*n*(a + b*Log[c*x^n]))/(d^3*x) - (b*e^2*n*x*(a + b*Log[c*x^n]))/(d^4*(d + e*x)) - (
b*e*n*Log[1 + d/(e*x)]*(a + b*Log[c*x^n]))/d^4 - (a + b*Log[c*x^n])^2/(d^3*x) - (e*(a + b*Log[c*x^n])^2)/(2*d^
2*(d + e*x)^2) + (2*e^2*x*(a + b*Log[c*x^n])^2)/(d^4*(d + e*x)) + (3*e*Log[1 + d/(e*x)]*(a + b*Log[c*x^n])^2)/
d^4 + (b^2*e*n^2*Log[d + e*x])/d^4 - (4*b*e*n*(a + b*Log[c*x^n])*Log[1 + (e*x)/d])/d^4 + (b^2*e*n^2*PolyLog[2,
 -(d/(e*x))])/d^4 - (6*b*e*n*(a + b*Log[c*x^n])*PolyLog[2, -(d/(e*x))])/d^4 - (4*b^2*e*n^2*PolyLog[2, -((e*x)/
d)])/d^4 - (6*b^2*e*n^2*PolyLog[3, -(d/(e*x))])/d^4

Rule 31

Int[((a_) + (b_.)*(x_))^(-1), x_Symbol] :> Simp[Log[RemoveContent[a + b*x, x]]/b, x] /; FreeQ[{a, b}, x]

Rule 2341

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))*((d_.)*(x_))^(m_.), x_Symbol] :> Simp[(d*x)^(m + 1)*((a + b*Log[c*x^
n])/(d*(m + 1))), x] - Simp[b*n*((d*x)^(m + 1)/(d*(m + 1)^2)), x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[m, -1
]

Rule 2342

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)*((d_.)*(x_))^(m_.), x_Symbol] :> Simp[(d*x)^(m + 1)*((a + b*Lo
g[c*x^n])^p/(d*(m + 1))), x] - Dist[b*n*(p/(m + 1)), Int[(d*x)^m*(a + b*Log[c*x^n])^(p - 1), x], x] /; FreeQ[{
a, b, c, d, m, n}, x] && NeQ[m, -1] && GtQ[p, 0]

Rule 2351

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))*((d_) + (e_.)*(x_)^(r_.))^(q_), x_Symbol] :> Simp[x*(d + e*x^r)^(q +
 1)*((a + b*Log[c*x^n])/d), x] - Dist[b*(n/d), Int[(d + e*x^r)^(q + 1), x], x] /; FreeQ[{a, b, c, d, e, n, q,
r}, x] && EqQ[r*(q + 1) + 1, 0]

Rule 2354

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)/((d_) + (e_.)*(x_)), x_Symbol] :> Simp[Log[1 + e*(x/d)]*((a +
b*Log[c*x^n])^p/e), x] - Dist[b*n*(p/e), Int[Log[1 + e*(x/d)]*((a + b*Log[c*x^n])^(p - 1)/x), x], x] /; FreeQ[
{a, b, c, d, e, n}, x] && IGtQ[p, 0]

Rule 2355

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)/((d_) + (e_.)*(x_))^2, x_Symbol] :> Simp[x*((a + b*Log[c*x^n])
^p/(d*(d + e*x))), x] - Dist[b*n*(p/d), Int[(a + b*Log[c*x^n])^(p - 1)/(d + e*x), x], x] /; FreeQ[{a, b, c, d,
 e, n, p}, x] && GtQ[p, 0]

Rule 2356

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)*((d_) + (e_.)*(x_))^(q_.), x_Symbol] :> Simp[(d + e*x)^(q + 1)
*((a + b*Log[c*x^n])^p/(e*(q + 1))), x] - Dist[b*n*(p/(e*(q + 1))), Int[((d + e*x)^(q + 1)*(a + b*Log[c*x^n])^
(p - 1))/x, x], x] /; FreeQ[{a, b, c, d, e, n, p, q}, x] && GtQ[p, 0] && NeQ[q, -1] && (EqQ[p, 1] || (Integers
Q[2*p, 2*q] &&  !IGtQ[q, 0]) || (EqQ[p, 2] && NeQ[q, 1]))

Rule 2379

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)/((x_)*((d_) + (e_.)*(x_)^(r_.))), x_Symbol] :> Simp[(-Log[1 +
d/(e*x^r)])*((a + b*Log[c*x^n])^p/(d*r)), x] + Dist[b*n*(p/(d*r)), Int[Log[1 + d/(e*x^r)]*((a + b*Log[c*x^n])^
(p - 1)/x), x], x] /; FreeQ[{a, b, c, d, e, n, r}, x] && IGtQ[p, 0]

Rule 2389

Int[(((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)*((d_) + (e_.)*(x_))^(q_))/(x_), x_Symbol] :> Dist[1/d, Int[(d
 + e*x)^(q + 1)*((a + b*Log[c*x^n])^p/x), x], x] - Dist[e/d, Int[(d + e*x)^q*(a + b*Log[c*x^n])^p, x], x] /; F
reeQ[{a, b, c, d, e, n}, x] && IGtQ[p, 0] && LtQ[q, -1] && IntegerQ[2*q]

Rule 2395

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)*((f_.)*(x_))^(m_.)*((d_) + (e_.)*(x_)^(r_.))^(q_.), x_Symbol]
:> With[{u = ExpandIntegrand[(a + b*Log[c*x^n])^p, (f*x)^m*(d + e*x^r)^q, x]}, Int[u, x] /; SumQ[u]] /; FreeQ[
{a, b, c, d, e, f, m, n, p, q, r}, x] && IntegerQ[q] && (GtQ[q, 0] || (IGtQ[p, 0] && IntegerQ[m] && IntegerQ[r
]))

Rule 2421

Int[(Log[(d_.)*((e_) + (f_.)*(x_)^(m_.))]*((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.))/(x_), x_Symbol] :> Simp
[(-PolyLog[2, (-d)*f*x^m])*((a + b*Log[c*x^n])^p/m), x] + Dist[b*n*(p/m), Int[PolyLog[2, (-d)*f*x^m]*((a + b*L
og[c*x^n])^(p - 1)/x), x], x] /; FreeQ[{a, b, c, d, e, f, m, n}, x] && IGtQ[p, 0] && EqQ[d*e, 1]

Rule 2438

Int[Log[(c_.)*((d_) + (e_.)*(x_)^(n_.))]/(x_), x_Symbol] :> Simp[-PolyLog[2, (-c)*e*x^n]/n, x] /; FreeQ[{c, d,
 e, n}, x] && EqQ[c*d, 1]

Rule 6724

Int[PolyLog[n_, (c_.)*((a_.) + (b_.)*(x_))^(p_.)]/((d_.) + (e_.)*(x_)), x_Symbol] :> Simp[PolyLog[n + 1, c*(a
+ b*x)^p]/(e*p), x] /; FreeQ[{a, b, c, d, e, n, p}, x] && EqQ[b*d, a*e]

Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {\left (a+b \log \left (c x^n\right )\right )^2}{d^3 x^2}+\frac {e^2 \left (a+b \log \left (c x^n\right )\right )^2}{d^2 (d+e x)^3}+\frac {2 e^2 \left (a+b \log \left (c x^n\right )\right )^2}{d^3 (d+e x)^2}-\frac {3 e \left (a+b \log \left (c x^n\right )\right )^2}{d^3 x (d+e x)}\right ) \, dx \\ & = \frac {\int \frac {\left (a+b \log \left (c x^n\right )\right )^2}{x^2} \, dx}{d^3}-\frac {(3 e) \int \frac {\left (a+b \log \left (c x^n\right )\right )^2}{x (d+e x)} \, dx}{d^3}+\frac {\left (2 e^2\right ) \int \frac {\left (a+b \log \left (c x^n\right )\right )^2}{(d+e x)^2} \, dx}{d^3}+\frac {e^2 \int \frac {\left (a+b \log \left (c x^n\right )\right )^2}{(d+e x)^3} \, dx}{d^2} \\ & = -\frac {\left (a+b \log \left (c x^n\right )\right )^2}{d^3 x}-\frac {e \left (a+b \log \left (c x^n\right )\right )^2}{2 d^2 (d+e x)^2}+\frac {2 e^2 x \left (a+b \log \left (c x^n\right )\right )^2}{d^4 (d+e x)}+\frac {3 e \log \left (1+\frac {d}{e x}\right ) \left (a+b \log \left (c x^n\right )\right )^2}{d^4}+\frac {(2 b n) \int \frac {a+b \log \left (c x^n\right )}{x^2} \, dx}{d^3}-\frac {(6 b e n) \int \frac {\log \left (1+\frac {d}{e x}\right ) \left (a+b \log \left (c x^n\right )\right )}{x} \, dx}{d^4}+\frac {(b e n) \int \frac {a+b \log \left (c x^n\right )}{x (d+e x)^2} \, dx}{d^2}-\frac {\left (4 b e^2 n\right ) \int \frac {a+b \log \left (c x^n\right )}{d+e x} \, dx}{d^4} \\ & = -\frac {2 b^2 n^2}{d^3 x}-\frac {2 b n \left (a+b \log \left (c x^n\right )\right )}{d^3 x}-\frac {\left (a+b \log \left (c x^n\right )\right )^2}{d^3 x}-\frac {e \left (a+b \log \left (c x^n\right )\right )^2}{2 d^2 (d+e x)^2}+\frac {2 e^2 x \left (a+b \log \left (c x^n\right )\right )^2}{d^4 (d+e x)}+\frac {3 e \log \left (1+\frac {d}{e x}\right ) \left (a+b \log \left (c x^n\right )\right )^2}{d^4}-\frac {4 b e n \left (a+b \log \left (c x^n\right )\right ) \log \left (1+\frac {e x}{d}\right )}{d^4}-\frac {6 b e n \left (a+b \log \left (c x^n\right )\right ) \text {Li}_2\left (-\frac {d}{e x}\right )}{d^4}+\frac {(b e n) \int \frac {a+b \log \left (c x^n\right )}{x (d+e x)} \, dx}{d^3}-\frac {\left (b e^2 n\right ) \int \frac {a+b \log \left (c x^n\right )}{(d+e x)^2} \, dx}{d^3}+\frac {\left (4 b^2 e n^2\right ) \int \frac {\log \left (1+\frac {e x}{d}\right )}{x} \, dx}{d^4}+\frac {\left (6 b^2 e n^2\right ) \int \frac {\text {Li}_2\left (-\frac {d}{e x}\right )}{x} \, dx}{d^4} \\ & = -\frac {2 b^2 n^2}{d^3 x}-\frac {2 b n \left (a+b \log \left (c x^n\right )\right )}{d^3 x}-\frac {b e^2 n x \left (a+b \log \left (c x^n\right )\right )}{d^4 (d+e x)}-\frac {b e n \log \left (1+\frac {d}{e x}\right ) \left (a+b \log \left (c x^n\right )\right )}{d^4}-\frac {\left (a+b \log \left (c x^n\right )\right )^2}{d^3 x}-\frac {e \left (a+b \log \left (c x^n\right )\right )^2}{2 d^2 (d+e x)^2}+\frac {2 e^2 x \left (a+b \log \left (c x^n\right )\right )^2}{d^4 (d+e x)}+\frac {3 e \log \left (1+\frac {d}{e x}\right ) \left (a+b \log \left (c x^n\right )\right )^2}{d^4}-\frac {4 b e n \left (a+b \log \left (c x^n\right )\right ) \log \left (1+\frac {e x}{d}\right )}{d^4}-\frac {6 b e n \left (a+b \log \left (c x^n\right )\right ) \text {Li}_2\left (-\frac {d}{e x}\right )}{d^4}-\frac {4 b^2 e n^2 \text {Li}_2\left (-\frac {e x}{d}\right )}{d^4}-\frac {6 b^2 e n^2 \text {Li}_3\left (-\frac {d}{e x}\right )}{d^4}+\frac {\left (b^2 e n^2\right ) \int \frac {\log \left (1+\frac {d}{e x}\right )}{x} \, dx}{d^4}+\frac {\left (b^2 e^2 n^2\right ) \int \frac {1}{d+e x} \, dx}{d^4} \\ & = -\frac {2 b^2 n^2}{d^3 x}-\frac {2 b n \left (a+b \log \left (c x^n\right )\right )}{d^3 x}-\frac {b e^2 n x \left (a+b \log \left (c x^n\right )\right )}{d^4 (d+e x)}-\frac {b e n \log \left (1+\frac {d}{e x}\right ) \left (a+b \log \left (c x^n\right )\right )}{d^4}-\frac {\left (a+b \log \left (c x^n\right )\right )^2}{d^3 x}-\frac {e \left (a+b \log \left (c x^n\right )\right )^2}{2 d^2 (d+e x)^2}+\frac {2 e^2 x \left (a+b \log \left (c x^n\right )\right )^2}{d^4 (d+e x)}+\frac {3 e \log \left (1+\frac {d}{e x}\right ) \left (a+b \log \left (c x^n\right )\right )^2}{d^4}+\frac {b^2 e n^2 \log (d+e x)}{d^4}-\frac {4 b e n \left (a+b \log \left (c x^n\right )\right ) \log \left (1+\frac {e x}{d}\right )}{d^4}+\frac {b^2 e n^2 \text {Li}_2\left (-\frac {d}{e x}\right )}{d^4}-\frac {6 b e n \left (a+b \log \left (c x^n\right )\right ) \text {Li}_2\left (-\frac {d}{e x}\right )}{d^4}-\frac {4 b^2 e n^2 \text {Li}_2\left (-\frac {e x}{d}\right )}{d^4}-\frac {6 b^2 e n^2 \text {Li}_3\left (-\frac {d}{e x}\right )}{d^4} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.29 (sec) , antiderivative size = 290, normalized size of antiderivative = 0.90 \[ \int \frac {\left (a+b \log \left (c x^n\right )\right )^2}{x^2 (d+e x)^3} \, dx=-\frac {\frac {4 b^2 d n^2}{x}+\frac {4 b d n \left (a+b \log \left (c x^n\right )\right )}{x}-\frac {2 b d e n \left (a+b \log \left (c x^n\right )\right )}{d+e x}-5 e \left (a+b \log \left (c x^n\right )\right )^2+\frac {2 d \left (a+b \log \left (c x^n\right )\right )^2}{x}+\frac {d^2 e \left (a+b \log \left (c x^n\right )\right )^2}{(d+e x)^2}+\frac {4 d e \left (a+b \log \left (c x^n\right )\right )^2}{d+e x}+\frac {2 e \left (a+b \log \left (c x^n\right )\right )^3}{b n}+2 b^2 e n^2 (\log (x)-\log (d+e x))+10 b e n \left (a+b \log \left (c x^n\right )\right ) \log \left (1+\frac {e x}{d}\right )-6 e \left (a+b \log \left (c x^n\right )\right )^2 \log \left (1+\frac {e x}{d}\right )+10 b^2 e n^2 \operatorname {PolyLog}\left (2,-\frac {e x}{d}\right )-12 b e n \left (a+b \log \left (c x^n\right )\right ) \operatorname {PolyLog}\left (2,-\frac {e x}{d}\right )+12 b^2 e n^2 \operatorname {PolyLog}\left (3,-\frac {e x}{d}\right )}{2 d^4} \]

[In]

Integrate[(a + b*Log[c*x^n])^2/(x^2*(d + e*x)^3),x]

[Out]

-1/2*((4*b^2*d*n^2)/x + (4*b*d*n*(a + b*Log[c*x^n]))/x - (2*b*d*e*n*(a + b*Log[c*x^n]))/(d + e*x) - 5*e*(a + b
*Log[c*x^n])^2 + (2*d*(a + b*Log[c*x^n])^2)/x + (d^2*e*(a + b*Log[c*x^n])^2)/(d + e*x)^2 + (4*d*e*(a + b*Log[c
*x^n])^2)/(d + e*x) + (2*e*(a + b*Log[c*x^n])^3)/(b*n) + 2*b^2*e*n^2*(Log[x] - Log[d + e*x]) + 10*b*e*n*(a + b
*Log[c*x^n])*Log[1 + (e*x)/d] - 6*e*(a + b*Log[c*x^n])^2*Log[1 + (e*x)/d] + 10*b^2*e*n^2*PolyLog[2, -((e*x)/d)
] - 12*b*e*n*(a + b*Log[c*x^n])*PolyLog[2, -((e*x)/d)] + 12*b^2*e*n^2*PolyLog[3, -((e*x)/d)])/d^4

Maple [C] (warning: unable to verify)

Result contains higher order function than in optimal. Order 9 vs. order 4.

Time = 0.50 (sec) , antiderivative size = 908, normalized size of antiderivative = 2.82

method result size
risch \(\text {Expression too large to display}\) \(908\)

[In]

int((a+b*ln(c*x^n))^2/x^2/(e*x+d)^3,x,method=_RETURNVERBOSE)

[Out]

-2*b^2*n*ln(x^n)/d^3/x-b^2*ln(x^n)^2/d^3/x+6*b^2/d^4*e*ln(x)*ln(e*x+d)*ln(-e*x/d)*n^2-6*b^2*n/d^4*e*ln(x^n)*ln
(e*x+d)*ln(-e*x/d)-6*b^2*e*n^2*polylog(3,-e*x/d)/d^4+(-I*b*Pi*csgn(I*c)*csgn(I*x^n)*csgn(I*c*x^n)+I*b*Pi*csgn(
I*c)*csgn(I*c*x^n)^2+I*b*Pi*csgn(I*x^n)*csgn(I*c*x^n)^2-I*b*Pi*csgn(I*c*x^n)^3+2*b*ln(c)+2*a)*b*(-1/2*ln(x^n)/
d^2/(e*x+d)^2*e+3*ln(x^n)/d^4*e*ln(e*x+d)-2*ln(x^n)/d^3*e/(e*x+d)-ln(x^n)/d^3/x-3*ln(x^n)/d^4*e*ln(x)-1/2*n*(-
3/d^4*e*ln(x)^2+6/d^4*e*(dilog(-e*x/d)+ln(e*x+d)*ln(-e*x/d))-1/d^3*e/(e*x+d)+5/d^4*e*ln(e*x+d)+2/d^3/x-5/d^4*e
*ln(x)))-2*b^2*ln(x^n)^2/d^3*e/(e*x+d)-1/2*b^2*ln(x^n)^2/d^2/(e*x+d)^2*e-3*b^2*ln(x^n)^2/d^4*e*ln(x)-b^2/d^4*n
^2*e*ln(x)-5/2*b^2/d^4*n^2*e*ln(x)^2+5*b^2/d^4*n^2*e*dilog(-e*x/d)-b^2/d^4*e*ln(x)^3*n^2+3*b^2*ln(x^n)^2/d^4*e
*ln(e*x+d)+b^2*n*ln(x^n)/d^3*e/(e*x+d)+1/4*(-I*b*Pi*csgn(I*c)*csgn(I*x^n)*csgn(I*c*x^n)+I*b*Pi*csgn(I*c)*csgn(
I*c*x^n)^2+I*b*Pi*csgn(I*x^n)*csgn(I*c*x^n)^2-I*b*Pi*csgn(I*c*x^n)^3+2*b*ln(c)+2*a)^2*(-1/2/d^2/(e*x+d)^2*e+3/
d^4*e*ln(e*x+d)-2/d^3*e/(e*x+d)-1/d^3/x-3/d^4*e*ln(x))+6*b^2/d^4*e*ln(x)*dilog(-e*x/d)*n^2-6*b^2*n/d^4*e*ln(x^
n)*dilog(-e*x/d)-3*b^2/d^4*e*n^2*ln(e*x+d)*ln(x)^2+3*b^2/d^4*e*n^2*ln(x)^2*ln(1+e*x/d)+6*b^2/d^4*e*n^2*ln(x)*p
olylog(2,-e*x/d)-5*b^2*n*ln(x^n)/d^4*e*ln(e*x+d)+5*b^2*n*ln(x^n)/d^4*e*ln(x)+5*b^2/d^4*n^2*e*ln(e*x+d)*ln(-e*x
/d)+3*b^2*n/d^4*e*ln(x^n)*ln(x)^2+b^2*e*n^2*ln(e*x+d)/d^4-2*b^2*n^2/d^3/x

Fricas [F]

\[ \int \frac {\left (a+b \log \left (c x^n\right )\right )^2}{x^2 (d+e x)^3} \, dx=\int { \frac {{\left (b \log \left (c x^{n}\right ) + a\right )}^{2}}{{\left (e x + d\right )}^{3} x^{2}} \,d x } \]

[In]

integrate((a+b*log(c*x^n))^2/x^2/(e*x+d)^3,x, algorithm="fricas")

[Out]

integral((b^2*log(c*x^n)^2 + 2*a*b*log(c*x^n) + a^2)/(e^3*x^5 + 3*d*e^2*x^4 + 3*d^2*e*x^3 + d^3*x^2), x)

Sympy [F]

\[ \int \frac {\left (a+b \log \left (c x^n\right )\right )^2}{x^2 (d+e x)^3} \, dx=\int \frac {\left (a + b \log {\left (c x^{n} \right )}\right )^{2}}{x^{2} \left (d + e x\right )^{3}}\, dx \]

[In]

integrate((a+b*ln(c*x**n))**2/x**2/(e*x+d)**3,x)

[Out]

Integral((a + b*log(c*x**n))**2/(x**2*(d + e*x)**3), x)

Maxima [F]

\[ \int \frac {\left (a+b \log \left (c x^n\right )\right )^2}{x^2 (d+e x)^3} \, dx=\int { \frac {{\left (b \log \left (c x^{n}\right ) + a\right )}^{2}}{{\left (e x + d\right )}^{3} x^{2}} \,d x } \]

[In]

integrate((a+b*log(c*x^n))^2/x^2/(e*x+d)^3,x, algorithm="maxima")

[Out]

-1/2*a^2*((6*e^2*x^2 + 9*d*e*x + 2*d^2)/(d^3*e^2*x^3 + 2*d^4*e*x^2 + d^5*x) - 6*e*log(e*x + d)/d^4 + 6*e*log(x
)/d^4) + integrate((b^2*log(c)^2 + b^2*log(x^n)^2 + 2*a*b*log(c) + 2*(b^2*log(c) + a*b)*log(x^n))/(e^3*x^5 + 3
*d*e^2*x^4 + 3*d^2*e*x^3 + d^3*x^2), x)

Giac [F]

\[ \int \frac {\left (a+b \log \left (c x^n\right )\right )^2}{x^2 (d+e x)^3} \, dx=\int { \frac {{\left (b \log \left (c x^{n}\right ) + a\right )}^{2}}{{\left (e x + d\right )}^{3} x^{2}} \,d x } \]

[In]

integrate((a+b*log(c*x^n))^2/x^2/(e*x+d)^3,x, algorithm="giac")

[Out]

integrate((b*log(c*x^n) + a)^2/((e*x + d)^3*x^2), x)

Mupad [F(-1)]

Timed out. \[ \int \frac {\left (a+b \log \left (c x^n\right )\right )^2}{x^2 (d+e x)^3} \, dx=\int \frac {{\left (a+b\,\ln \left (c\,x^n\right )\right )}^2}{x^2\,{\left (d+e\,x\right )}^3} \,d x \]

[In]

int((a + b*log(c*x^n))^2/(x^2*(d + e*x)^3),x)

[Out]

int((a + b*log(c*x^n))^2/(x^2*(d + e*x)^3), x)